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-0.001x^2+3x=545+.60x
We move all terms to the left:
-0.001x^2+3x-(545+.60x)=0
We add all the numbers together, and all the variables
-0.001x^2+3x-(.60x+545)=0
We get rid of parentheses
-0.001x^2+3x-.60x-545=0
We add all the numbers together, and all the variables
-0.001x^2+2.4x-545=0
a = -0.001; b = 2.4; c = -545;
Δ = b2-4ac
Δ = 2.42-4·(-0.001)·(-545)
Δ = 3.58
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.4)-\sqrt{3.58}}{2*-0.001}=\frac{-2.4-\sqrt{3.58}}{-0.002} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.4)+\sqrt{3.58}}{2*-0.001}=\frac{-2.4+\sqrt{3.58}}{-0.002} $
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